AD&D Demystified: Missile Fire Into Melee

Nothgrim (2) and Thorkell (3) are in trouble! They are currently engaged in melee with a troglodyte (4), hobgoblin (5), and two bugbears (6 & 7)! It’s up to Elestren (1)!

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First the DM must assign probabilities to each melee participant according to size.

  • Small: 0.5
  • Medium: 1
  • Large (those not too much much larger than man-size): 1.5

Nothgrim (2) is dwarf, so his size is small. Thorkell (3) is a human, so his size is medium. Therefore: 0.5 + 1 = 1.5 = 1 (rounded down)

Bugbears are large; hobgoblins and troglodytes are medium. Therefore:  1.5 + 1.5 + 1 + 1 = 5

The ratio is 1 :  5. This means that if 6 arrows were fired, 1 would have a chance to hit Elestren’s (1) friends (2 & 3) and 5 would have a chance to hit the monsters (4. 5. 6. & 7). However, since Elestren (1) is only firing one arrow this round, the DM must convert the ratio to percentages.

  • Chance it will hit party: 1/6 = 17%
  • Chance it will hit monsters: 5/6 = 83%

The DM then rolls 2d10 to determine which side gets hit. The DM rolls a 15! This means that either Nothgrim (2) or Thorkell (3) has a chance to get hit. The DM then randomly determines who. Suppose even on 1d10 means Nothgrim (2) and odd means Thorkell (3).

The DM rolls a 7. Now a to hit-roll must be made against Thorkell (3).

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