Nothgrim (2) and Thorkell (3) are in trouble! They are currently engaged in melee with a troglodyte (4), hobgoblin (5), and two bugbears (6 & 7)! It’s up to Elestren (1)!
First the DM must assign probabilities to each melee participant according to size.
- Small: 0.5
- Medium: 1
- Large (those not too much much larger than man-size): 1.5
Nothgrim (2) is dwarf, so his size is small. Thorkell (3) is a human, so his size is medium. Therefore: 0.5 + 1 = 1.5 = 1 (rounded down)
Bugbears are large; hobgoblins and troglodytes are medium. Therefore: 1.5 + 1.5 + 1 + 1 = 5
The ratio is 1 : 5. This means that if 6 arrows were fired, 1 would have a chance to hit Elestren’s (1) friends (2 & 3) and 5 would have a chance to hit the monsters (4. 5. 6. & 7). However, since Elestren (1) is only firing one arrow this round, the DM must convert the ratio to percentages.
- Chance it will hit party: 1/6 = 17%
- Chance it will hit monsters: 5/6 = 83%
The DM then rolls 2d10 to determine which side gets hit. The DM rolls a 15! This means that either Nothgrim (2) or Thorkell (3) has a chance to get hit. The DM then randomly determines who. Suppose even on 1d10 means Nothgrim (2) and odd means Thorkell (3).
The DM rolls a 7. Now a to hit-roll must be made against Thorkell (3).